piątek, 24 marca 2017
Risk matrix in R (interesting readings)
1) Risk matrix examples http://davidmeza1.github.io/2015/12/17/2015-12-17-Creating-a-Risk-Matrix-in-R.html
2) Use ggrepel instead of jitter https://cran.r-project.org/web/packages/ggrepel/vignettes/ggrepel.html
for multiple points.
3) Is there ggrepel for Excel (?) http://stackoverflow.com/questions/30294041/excel-bubble-chart-overlapping-data-label
wtorek, 21 marca 2017
Stats Day2: Covariance
Covariance
Cov(for sample) = sum[(x - śr(x))*(y-śr(y))]/n-1 ... we are interesting in the sign. Does not provide strength. Is not standardized.
Covariance matrix...diagonal shows variance of each variable, off-diagonal show covariances betw. each variable pair.
Correlation (Pearson, r)
r =Cov(x,y)/[SD(x)* SD(y)]
Cov(for sample) = sum[(x - śr(x))*(y-śr(y))]/n-1 ... we are interesting in the sign. Does not provide strength. Is not standardized.
Covariance matrix...diagonal shows variance of each variable, off-diagonal show covariances betw. each variable pair.
Correlation (Pearson, r)
r =Cov(x,y)/[SD(x)* SD(y)]
poniedziałek, 20 marca 2017
Stats Day1
With Spring day 1 I start regular intro statistics study:
My notes from day 1:
Standard Error of Mean (SD of a sample):
SD/ root(n) - the larger sample size, the error decreases,
Z-Score: (x-mean)/SD
https://en.wikipedia.org/wiki/Standard_score
T-Score:
Conversion Score = z * (NewSD)+NewMean
NewSD for T-Score = 10 and NewMean = 50
T-Score = Z-Score*10+50
More: Essentials of Testing and Assessment: A Practical Guide for Counselors ...Autorzy Edward S. Neukrug,R. Charles Fawcett p 133 (fragment available online via Google)
Coefficient of Variation
CV% = (SD/Mean)*100
My notes from day 1:
Standard Error of Mean (SD of a sample):
SD/ root(n) - the larger sample size, the error decreases,
Z-Score: (x-mean)/SD
https://en.wikipedia.org/wiki/Standard_score
T-Score:
Conversion Score = z * (NewSD)+NewMean
NewSD for T-Score = 10 and NewMean = 50
T-Score = Z-Score*10+50
More: Essentials of Testing and Assessment: A Practical Guide for Counselors ...Autorzy Edward S. Neukrug,R. Charles Fawcett p 133 (fragment available online via Google)
Coefficient of Variation
CV% = (SD/Mean)*100
ExcelVBA: From recorded macro to reusable function.
Problem: with each change in slicer, pivot chart formatting changes.
So I want all my lables vertical (and with each change the damn thing returns to horizontal). My recorded macro did not return anything sensible. Lecture on chart label properties brought me to this solution:
Sub Macro1()
'
' Wersja "Recorder"
'
Dim mySrs As Series
With ActiveSheet.ChartObjects("chValueofOffers").Chart
.SeriesCollection(1).DataLabels.Orientation = xlUpward
.SeriesCollection(2).DataLabels.Orientation = xlUpward
End With
Next I wanted to iterate through series collection so that I do not need to change macro for more series:
Sub Macro2()
'
' Wersja "Obiektowo pętlowa"
'
Set seriesCol = ActiveSheet.ChartObjects("chValueofOffers").Chart.SeriesCollection
For Each mySeries In seriesCol
mySeries.DataLabels.Orientation = xlUpward
Next
Set seriesCol = ActiveSheet.ChartObjects("chValueofOffersTotal").Chart.SeriesCollection
End Sub
Finally... what if I have several charts on the same sheet that need vertical labels. Why not making it a reusable function with chart name as attribute. Now... with each change in the slicer the labels in the two charts get corrected to vertical.
Private Function DataLabelsVertical(mySheet As String, chtName As String)
Dim mySeries As Series
Set seriesCol = Worksheets(mySheet).ChartObjects(chtName).Chart.SeriesCollection
For Each mySeries In seriesCol
mySeries.DataLabels.Orientation = xlUpward
Next
End Function
Private Sub Worksheet_Change(ByVal Target As Range)
DataLabelsVertical "Value_tenders", "chValueofOffers"
DataLabelsVertical "Value_tenders", "chValueofOffersTotal"
DataLabelsVertical "Status", "chStatusValue"
DataLabelsVertical "Status", "chStatusValueTotal"
End Sub
End Function
Sources:
http://www.java2s.com/Code/VBA-Excel-Access-Word/Excel/Loopthrougheachseriesinchartandaltermarkercolors.htm
http://stackoverflow.com/questions/21165581/vba-looping-through-all-series-within-all-charts
So I want all my lables vertical (and with each change the damn thing returns to horizontal). My recorded macro did not return anything sensible. Lecture on chart label properties brought me to this solution:
Sub Macro1()
'
' Wersja "Recorder"
'
Dim mySrs As Series
With ActiveSheet.ChartObjects("chValueofOffers").Chart
.SeriesCollection(1).DataLabels.Orientation = xlUpward
.SeriesCollection(2).DataLabels.Orientation = xlUpward
End With
Next I wanted to iterate through series collection so that I do not need to change macro for more series:
Sub Macro2()
'
' Wersja "Obiektowo pętlowa"
'
Set seriesCol = ActiveSheet.ChartObjects("chValueofOffers").Chart.SeriesCollection
For Each mySeries In seriesCol
mySeries.DataLabels.Orientation = xlUpward
Next
Set seriesCol = ActiveSheet.ChartObjects("chValueofOffersTotal").Chart.SeriesCollection
End Sub
Finally... what if I have several charts on the same sheet that need vertical labels. Why not making it a reusable function with chart name as attribute. Now... with each change in the slicer the labels in the two charts get corrected to vertical.
Private Function DataLabelsVertical(mySheet As String, chtName As String)
Dim mySeries As Series
Set seriesCol = Worksheets(mySheet).ChartObjects(chtName).Chart.SeriesCollection
For Each mySeries In seriesCol
mySeries.DataLabels.Orientation = xlUpward
Next
End Function
Private Sub Worksheet_Change(ByVal Target As Range)
DataLabelsVertical "Value_tenders", "chValueofOffers"
DataLabelsVertical "Value_tenders", "chValueofOffersTotal"
DataLabelsVertical "Status", "chStatusValue"
DataLabelsVertical "Status", "chStatusValueTotal"
End Sub
End Function
Sources:
http://www.java2s.com/Code/VBA-Excel-Access-Word/Excel/Loopthrougheachseriesinchartandaltermarkercolors.htm
http://stackoverflow.com/questions/21165581/vba-looping-through-all-series-within-all-charts
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